The coordinates of the vertices of △jkl are j(3, 4), k(3, 1) , and l(1, 1) . the coordinates of the vertices of △j′k′l′ are j′(−3,−5), k′(−3,−2), and l′(−1,−2). drag and drop the answers into the boxes to correctly complete the statement. a sequence of transformations that maps △jkl to △j′k′l′ is a followed by a

The correct answer is:

A 180° rotation followed by a translation 1 unit down.

Explanation:

The points are mapped as follows:

J(3, 4)→J'(-3, -5)

K(3, 1)→K'(-3, -2)

L(1, 1)→L'(-1, -2)

A 180° rotation maps a point (x, y) to (-x, -y).  This would map

J(3, 4)→(-3, -4)

K(3, 1)→(-3, -1)

L(1, 1)→(-1, -1)

The difference between these points and the image points are that each y-coordinate of the image is 1 lower than these.  This means a translation 1 unit down would result in the image points.

Step-by-step explanation:

Given are the coordinates of vertices of △JKL are J(3, 4), K(3, 1) , and L(1, 1) . The coordinates of the vertices of △J′K′L′ are J′(−3,−5), K′(−3,−2), and L′(−1,−2).

On comparison we find that each x  coordinate has changed sign and y coordinate changed sign and 1 unit less.

Hence correct transformation would be

i) A rotation of 180 degrees about the origin.  This makes the coordinates as

(−3,−4), (−3,−1), and (−1,−1)

ii) Now shift 1 unit down vertically  sothat we get the triangle J'K'L'

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2