An equation and the steps to solve it are shown below: 3x − one over two (8x − 2) = 4 step 1: 3x − 4x + 1 = 4 step 2: x + 1 = 4 step 3: x + 1 − 1 = 4 − 1 step 4: x = 3 which step was the error made and why? a) step 1, because incorrect signs have been used b) step 2, because the terms have been added incorrectly c) step 3, because numbers have been added to both sides of the equation d) no error was made fifty points for correct answer (reporting wrongs/fakes)

It should be B.
The when you have 3x-4x it came out to x in the equation which should have been -x.
The equation should come out to being x=-3.
3(-3)-.5(8(-3)-2)=4
-9-.5(-26)=4
-9+13=4
4=4

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12