10 points + brainliest can someone me with this question? a basketball is shot from 2 meters up at an angle of 60° above the x axis at an initial velocity of 9 m/s. what is the maximum height the ball will reach?

initial distance up = 2

initial velocity component up = 9 sin 60 = 7.79

v = 9 sin 60 - 9.8 t

when v = 0, we are there

9.8 t = 7.79

t = .795 seconds to top

h = 2 + 7.79(.795) - 4.9(.795^2)

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i dont understand the question? ?

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