Ahoneybee flaps its wings 200 times per second. how much time is required for one wingbeat? give your answere in millisecond

The time required for one wing beat is 5 milliseconds.

Explanation

Lets assume, the time required for one wing beat is   seconds

So, the time required for 200 wing beat seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

So, the time required for one wing beat is 5 milliseconds.

my answer got deleted but it's a

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560