Ahorse race has 13 entries and one person owns 5 of those horses. assuming that there are no ties, what is the probability that those five horses finish first, second, third, fourth, and fifth (regardless of order)? the probability first, second, third, fourth, and fifth is nothing.

There are 13 entries in total  

The owner has 5 horses.

If each horses has  the same  probability of winning, then the probability that the owners

Horses will come in first, second, third, and fourth will be as follows:

It was only specified that one of these horses needed to be in each position  

This makes it is a combination type problem because order does not matter  

We 5 horses

The probability that one of those 5 horses will be first is 5/13

The probability that one of those remaining  4 horses will be second is 4/12

The probability that one of those remaining  3 horses will be third is 3/11

The probability that one of those remaining 2 horses will be fourth is 2/10

The probability that one of those remaining 1 horses will be fifth is 5/9    

The total probability is that 0.00389

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.