Assume the weight of a randomly chosen american passenger car is a uniformly distributed random variable ranging from 2,500 pounds to 4,500 pounds. (a) what is the mean weight of a randomly chosen vehicle?

Let X= weight of the passenger car

a/q, X is u(2500,4500)

we know that mean= a+b/2

so a=2500, b=4500

hence, mean=2500+4500/2

=3500 pounds

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

i believe that the answer is

b. y-1=-2(x-4)

hope this !