Mathematics, 12.07.2019 04:30 suttonfae336

The velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented by the table. the acceleration due to gravity is the constant of variation. what is the acceleration due to gravity of a falling object? 4.9 9.8 10.2 19.6

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It is given to us that the velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented by the table (which is not given to us). The acceleration due to gravity is the constant of variation. Now, we know, from basic physics that the value of the acceleration due to gravity in the SI unit is 9.8 m/s^2. Therefore, the second option is the correct option.

Answer from: tiny2007

Correct option is b) $\rm 9.8 \; m/sec^2$

Step-by-step explanation:

Given :

Table -

Time (sec) Velocity (m/sec)

0 0

1 9.8

2 19.6

3 29.4

4 39.2

Velocity varies directly with time.

Solution :

We know that,

$\rm v = u +at$ --- (1)

where, v is the final velocity in m/sec, u is the initial velocity in m/sec, a is the acceleration in $\rm m/sec^2$ and t is the time in sec.

So, from table we have

t = 1 sec, u = 0 m/sec, v = 9.8 m/sec

putting this values in equation (1), we get

9.8=0+a(1)

$\rm a = 9.8\;m/sec^2$

Therefore, option b) is correct.

For more information, refer the link given below

link

Answer from: Quest

536

step-by-step explanation:

Answer from: Quest

the length of o'p' is $1.5\times op$ .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

$k=\frac{o'p'}{op}$

the scale factor is 1.5.

$1.5=\frac{o'p'}{op}$

multiply both sides by op.

$1.5\times op=o'p'$

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is $1.5\times op$ .

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