Triangle xyz, with vertices x(-1, -3), y(-1, -1), and z(-3, -1), is translated 2 units right and one unit down to form triangle x′y′z′. what are the coordinates of the vertices of triangle x′y′z′? a. x′(1, 4), y′(1, -2), and z′(-1, 0) b. x′(1, -4), y′(1, -2), and z′(-1, -2) c. x′(-1, 4), y′(-1, 2), and z′(1, 0) d. x′(1, -4), y′(1, -2), and z′(-1, 0) e. x′(-3, -4), y′(-3, -2), and z′(-5, -2)

The rule of transformation 2 units right and one unit down will be as following:

( x , y ) ⇒⇒⇒ ( x+2 , y-1 )

The vertices of triangle XYZ are X(-1, -3), Y(-1, -1), and Z(-3, -1)

After transformation the coordinates of the image X′Y′Z′ can be calculated as following:

X' = ( -1+2 , -3-1) = (1 , -4)

Y' = ( -1+2 , -1-1) = (1 , -2)

Z' = ( -3+2 , -1-1 ) = ( -1 , -2 )

So, the correct answer is option B

B. X′(1, -4), Y′(1, -2), and Z′(-1, -2)

250

step-by-step explanation:

1,918

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