Keep the function x(t)=8∗t−2∗t∗t in the expression evaluator. what is the value of the person’s acceleration a at t=2s?

we are given

position function as

we know that acceleration is second derivative of position

so, firstly, we will find first derivative

now, we can simplify it

now, we can find derivative again

now, we can plug t=2

and we get

so,

the value of the person’s acceleration a at t=2s is -4..........Answer

a) 7x=7

step-by-step explanation: