Find three consecutive odd integers whose sum is 117

First odd integer: 2k+1 (note: using 2k+1 insures it is an odd integer)

Second odd integer: 2k+3

Third odd integer: 2k+5

First + Second + Third = 117

2k+1 + 2k+3 + 2k+5 = 117 substituted for First, Second, and Third

6k + 9 = 117 added like terms

6k = 108 subtracted 7 from both sides

k = 18

First: 2k + 1 = 2(18) + 1 = 36 + 1 = 37

Second: 2k + 3 = 2(18) + 3 = 36 + 3 = 39

Third: 2k + 5 = 2(18) + 5 = 36 + 5 = 41

37, 39, 41

step-by-step explanation:

there are 36 inches in a yard

25 : 36 = 0.69 yards (you can round to 0.70)

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )