"a frog is sitting on a stump 12 feet above the ground. it hops off the stump and lands on the ground 6 feet away. during its leap, its height h is given by the equation h equals negative 0.5 x squared plus x plus 12 where x is the distance in feet from the base of the stump, and h is height in feet. how far was the frog from the base of the stump when it was 0.5 feet above the ground? "

Solution:

Given equation: h = -0.5x² + x + 12

h = 0.5

-0.5x² + x + 12 = 0.5

-0.5x² + x + 11.5 = 0

Find the roots of quadratic equation.

x = ((-b )+- √(b² - 4ac))/2a

= ((-1 )+- √(1² - 4*(-0.5)*(11.5)))/2(1)

= -3.9, 5.9

The distance will not be negative.

Hence, the distance is 5.9.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

y=sec x is the correct answer

~batmans wife dun dun