2e^3x=4e^5x. find x using log. show work

2 = 4

= 2divided both sides by 2

ln ( ) = ln (2 ) applied "ln" to both sides

ln ( ) = ln 2 + ln tex] e^{5x} [/tex] ) applied the log product rule

3x = ln 2 + 5x applied "ln e = 1"

-2x = ln 2 subtracted 5x from both sides

x = divided both sides by "-2"

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: