The length of a rectangle is 4 centimeters less than twice it’s width. the perimeter of the rectangle is 34vm. what are the dimensions of the rectangle?

l = 2w - 4

Because we're solving for 2l + 2w, that can be simplified to

2(2w - 4) + 2w = 34

4w - 8 + 2w = 34

6w - 8 = 34

6w = 42

w = 7

Knowing this, we can input w:

2(7) + 2l = 34

14 + 2L = 34

2l = 20

l = 10

L = 10, W = 7, Option C

answer: what statements

step-by-step explanation if you write the statements down then i could you.