The sum of three consecutive integers is 393. find the integers.

Remark

Consecutive numbers are given as

x , x + 1 , x + 2

when they are added together you get x + x + 1 + x + 2 = 3x + 3

3x + 3 = 393 Subtract 3 from both sides.

3x = 393 - 3

3x = 390 Divide by 3

x = 390/3

x = 130

So the three numbers are

130

131

132

Let x represent the first integer

then the second integer is x + 1

and the third integer is x + 2

(x) + (x + 1) + (x + 2) = 393 the sum of the 3 integers is 393

3x + 3 = 393 added like terms

3x = 390 subtracted 3 from both sides

x = 130 divided both sides by 3

since x = 130, then x + 1 = 131, and x + 2 = 132

130, 131, 132

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it