Each cow has 4 legs and each chicken has 2 legs. if a boy counts 42 heads and 144 feet, how many cows are there?

Solution:

we are given that

Each cow has 4 legs and each chicken has 2 legs.

A boy counts 42 heads and 144 feet.

we have been asked to find how many cows are there?

Let there are x cows and y chicken.

Then we can write

Hence Number of cows=30

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3