There was a total of 548 dollars collected for tickets to the school play. the adult tickets cost 6 dollars, and the student tickets cost 4 dollars. if 12 more student tickets were sold than adult tickets, find the numbers of adult and student tickets sold.

This is a systems of equations problem. To begin, we need to set up our equations.

If there was a total of 548 dollars collected, and adult tickets cost $6, and students tickets $4, this equation represents that situation.

6a + 4s = 548

The variable a stands for adult, and variable s for student. Now, if 12 more student tickets were sold than adults, this would represent that.

a + 12 = s

Now we can set it up as a systems of equations.

Because s = a + 12, we can plug that in into the other equation.

6a + 4(a + 12) = 548

Distribute 4.

6a + 4a + 48 = 548

Combine like terms.

10a + 48 = 548

Subtract 48 from both sides.

10a = 500

Divide both sides by 10.

a = 50

Plug a into the original equation.

50 + 12 = s

Combine like terms.

62 = s

one of each metals

step-by-step explanation:

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation: