In triangle abc, the measure of angle b is 18° more than three times the measure of angle a. the measure of angle c is 42° more than the measure of angle a. find the measure of each angle.

A = A

B = 3A + 18

C = A + 42

The sum of the angles of a triangle equals 180°

A + B + C = 180

(A) + (3A + 18) + (A + 42) = 180

5A + 60 = 180

5A = 120

A = 24

B = 3A + 18 = 3(24) + 18 = 72 + 18 = 90

C = A + 42 = C = 24 + 42 = 66

A=24, B=90, C=66

5

step-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4