2x(3x+5)+3(3x+5)=ax^2+bf+c in the equation above a, b, and c are constants. if the equation is true for all values of x what is the value of b

2x(3x + 5) + 3(3x + 5) = ax² + bf + c

2x.3x + 2x.5 + 3.3x + 3.5 = ax² + bf + c

6x² + 10x + 9x + 15 = ax² + bf + c

6x² + 19x + 15 = ax² + bf + c

6x² = ax²

6 = a

19x = bf

15 = c

As the question says, b is constant, so he can't be a variable, so he only can be 19 and f be x

19x = bf

19 = b

x = f

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: