After 5 tests dara's average score was 88 what score must she average on the next two tests to have a seven-test average of 90?

After 5 tests, her average was 88. To have a seven-test average of 90, the total must be:

Her average after 5 tests was 88. Her total score on the 5 tests is:

Subtract:

Find the average by dividing by 2:

Her average must be 95

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.