How do you factor 9x^3 + 64 ( show steps)

First, let's review the formula for the "sum of two cubes:"

a^3 + b^3 = (a + b)(a^2 - ab + b^2).

Unfortunately, 9 is not a perfect cube. The cube root of 9 is 9^(1/3), and the square of the cube root of 9 is therefore 9^(2/3).

Thus,

9x^3 + 64 = (9^(1/3)*x + 4) * (9^(2/3)x^2 - 4*9^(1/3) + 16)

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4