Amini bag of skittles has 3 lemon, 4 grape, 4 orange and 2 lime skittles. what is the probability of randomly pulling an orange skittle out first and eating it and then pulling a lime skittle out of the bag next?

Step-by-step explanation:

Given : A mini bag of Skittles has 3 lemon, 4 grape, 4 orange and 2 lime Skittles.

Total Skittles = 3+4+4+2=13

Probability of pulling an orange Skittle out first :  P(First orange)

Since the second skittles is drawn without replacement , so after drawing one skittle , the remaining skittles = 13-1=12

So , P(Second skittle is lime) =

Since the events of pulling any Skittle are independent .

So , P( Orange then lime)= P(First orange) x P(Second skittle is lime)

∴ The probability of randomly pulling an orange Skittle out first and eating it and then pulling a lime Skittle out of the bag next =

exactly you go it

step-by-step explanation:

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25