What are the x- and y-intercepts of the line tangent to the circle (x – 2)2 + (y – 2)2 = 25 at the point (5, 6)? pleasw

I'm assuming you have. The first thing we do is find the slope of the tangent line by finding the derivative of the equation at the point (5,6).

expanding the equation

x^2 - 4x + 4 + y^2 - 4y + 4 = 25

Finding the derivative

2x - 4 + 2y y' - 4y' = 0

y'( 2y - 4) = 4 - 2x

y' = (4 - 2x) / (2y - 4)

at the point (5,6) the slope = y' = (4 - 10) / (12 - 4) = -3/4

So the equation of tangent line is y - 6 = -3/4( x - 5)

y = -3/4x + 39/4

so the y intercept = =3/4(0) + 39/4 = 39/4 Answer

and x intercept = -39/4 / - 3/4 = 13 Answer

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.