Abox contains seven action, six comedies, eight dramas, and five science fiction films. find the probability of choosing a comedy, putting it back and choosing a drama. i cant figure out really how to do this question either.

7 action, 6 comedies, 8 dramas and 5 science fiction. So our sample space or possible outcomes is 7+6+8+5, or 26.

one thing to note is that AND means multiplication.

P(comedy) will be 6/26, favorable outimes over possible outcomes, and then we put it back, because we're putting it back in the box, the sample space is again 26, therefore P(drama) is 8/26, and then we multiply both.

The required probability = (6/26)*(8/26) = 0.071

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!