Find the range of the function. f(x) = x2 + 3

To find the range, you need to locate the vertex:

equation for vertex = ax^2 + bx +c

in x^2 + 3, a = 1, b = 0 and c = 3

now vertex form = a(x+d)^2 +e

d = b/2a = 0/2*1 = 0

e = c-b^2/4a = 3-0^2/4*1 = 3

The equation becomes: (x+0)^2 +3.

The range is Y ≥ 3 ( greater than or equal to 3)

Range:

Step-by-step explanation:

We have been given a function . We are asked to find the range of our given function.

We know that range of a function is values of dependent variable (y) for which function is defined.

We can see that our given parabola is in vertex form as with a vertex at point .

Since our given parabola is an upward opening parabola, so point is the minimum point.

We know that the range of an exponential function is form with a vertex at (h,k) is:

If , then range is

If , then range is

Since the value of a is positive and , therefore, the range of our given function would be that is .

yes

step-by-step explanation:

mx+89b(-98)nb

step-by-step explanation: