Anumber is divided by 3. then 14 is added to the quotient. the result is 33. what is the orginal number?

let "a number" = x

a number is divided by 3 => x/3

14 is added to the quotient => (x/3) + 14

The result is 33 => " = 33"

Solve for x

(x/3) + 14 = 33

Isolate the x. Note the equal sign. What you do to one side you do the other.

Subtract 14 from both sides

(x/3) + 14 (-14) = 33 (-14)

x/3 = 19

Isolate the x. Multiply 3 to both sides

x/3(3) = 19(3)

x = 19(3)

x = 57

57 is your original number

hope this helps

i think 1: 2

step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents