1. a regular pentagon has side length 12 cm. the perimeter of the pentagon is 60 cm and the area is 247.7 cm2. a second pentagon has side lengths equal to 18 cm. find the perimeter of the second pentagon. 2. the ratio of the areas of two similar polygons is 49: 36. if the perimeter of the first polygon is 15 cm, what is the perimeter of the second polygon? round to the nearest hundredth.

Step-by-step explanation:

1) Since both regular pentagons are similar we have sides are proportional

Perimeter of first pentagon =60 cm

One side = 60/5 =12 cm

Ratio of I pentagon side: II=12:18 =2:3

Perimeter ratio = 2:3

2:3 = 60:x

Hence x = 90 cm.

Perimeter of second = 90 cm

2) When areas have ratio 49:36

sides will have ratio as square roots =7:6

Perimeter also ratio 7:6

Hence 7:6= 15:x

x =Perimeter of II pentagon =90/7 = 12.86 cm.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)