Elizabeth brought a box of donuts to share. there are two-dozen (24) donuts in the box, all identical in size, shape, and color. threethree are jelly-filled, 44 are lemon-filled, and 1717 are custard-filled. you randomly select one donut, eat it, and select another donut. find the probability of selecting two custardcustard-filled donuts in a row.

( I'm assuming it's supposed to say 3 jelly-filled, 4 lemon-filled, and 17 custard-filled since there are only 24 donuts)

this means that 3 out of 24 are jelly (3/24)
4 out of 24 are lemon (4/24)
and 17 out of 24 are custard (17/24)
the probability of eating a custard donut is then 17/24
now there are 23 donuts left, and 16 are custard. the probability of eating a custard donut is now 16/23. however, the probability of both of these happening is found by multiplying these 2 separate probabilities:

17/24 × 16/23 = 272/552
this probability is then simplified:
(272÷8)/(552÷8)= 34/69
so, the answer is 34/69, which is about a 49.3% chance

Line the mark up so you will find your answer

Number 5 is 50 degreesnumber 6 is 45 degreesnumber 7 is 60 degreesnumber 8 is 45 degrees