One student ate 3/20 of all candies and another 1.2 lb. the second student ate 3/5 of the candies and the remaining 0.3 lb. what weight of candies did they each eat?

Let us say there are x number of candies .

For first student,

He ate 3/20 of all candies, so 3/20 (x)

He also ate 1.2 lb of candies.

Total candies first student ate = (3/20) x +1.2

Second student ate 3/5 of all candies that is (3/5)x

He also ate 0.3 lb of candies.

Total candies second student ate = (3/5)x +0.3

Since total candies for both will be same, so equating the two expressions

x=2

So there are 2 lb of candies in total.

First student ate = 0.3 +1.2 = 1.5lb of candies.

Second student ate = 1.5 lb of candies

24+x=y

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°