For every gallon of water in a swimming pool you’re instructed to add four grams of chlorine. how many grams of chlorine would you add to a pool containing 13 gallons of water

So, we're told that for every gallon of water in the swimming pool there should be four grams of chlorine. In the most simple terms, it's simply we should have a ratio 4grams chlorine:1 gallon of water. We can solve it like any other proportion question as a result, giving us:

To solve this we want to multiply both sides by 13 gallons to get rid of the gallons and also to isolate the x, so:

Which means we should add 42 grams of chlorine in a pool containing 13 gallons of watter.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)