Aball was kicked into the air from a balcony 20 feet above the ground, and the ball's height above the ground in feet t seconds after the ball was kicked is  h(t) = 20 - 16t2  + 32t. what was the maximum height, in feet, of the ball above the ground after it was kicked?

Covert the equation to vertex form:-

- 16t^2 + 32t + 20

= -16(t^2 - 2)^2 + 20

= -16(t - 1)^2 - 1) + 20

= -16(t - 1)^1 + 16 + 20

= 36 feet answer

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

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