Acog company produces 20 cogs a day, 4 of which are defective. find the probability of selecting 4 cogs from the 20 produced where none are defective?

Probability of selecting a non-detective cog = 16/20

Required Probability = 16/20 * 15/19 * 14/18* 13/17 = 364/969

= 0.3756 or 37.56 % answer

=

Step-by-step explanation:

Number of cogs produced by the company = 20

Number of cogs which are defective = 4

no. of cogs which are not defective = 20 - 4

                                                           = 16

Now, we need to find the probability of selecting 4 cogs which are not defective

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

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step-by-step explanation:

i wish i could u