How do you find an equation for the line tangent to the circle x2+y2=25 at the point (3, -4)?

Alright, lets get started.

The curve circle is given as

We could find the slope by diffentiating it.

We hve given the point (3,-4). Putting its value as (x,y)

= m

The equation of line is y = mx + c

Putting the value of m and c in equation, Hence the eqution will be

Multiplying the complete equation with 4

or

: Answer

Hope it will help :)

720

step-by-step explanation:

first i did work 2nd i did work and 3rd i did work

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°