Consider the line find the equation of the line that is perpendicular to this line and passes through the point find the equation of the line that is parallel to this line and passes through the point equation of perpendicular line: equation of parallel line:

Firstly we put the equation of the line into form so we can find the gradient.

So we see the gradient of the line is -5/4. The gradient of a line perpendicular to a line with gradient m is so we see the gradient of a line perpendicular to your line is .

So we know it's a line with gradient 4/5 passing through (5,2) hence

.

For the parallel line, you use the same gradient as the original which is -5/4 and using the fact that it passes through (5,2) repeat the process from above to find the line. I'll leave this one up to you!

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m