Renee has a bag of 6 candies, 4 of which are sweet and 2 of which are sour. jack picks two candies simultaneously and at random. what is the chance that exactly 1 of the candies he has picked is sour?

She takes 2 candies, and must get 1 sweet and one sour.

The first candy must be sweet followed by a candy that is sour or the first must be sour followed by a sweet one.

Probability of first candy being sweet: p(first sweet) = 4/6

Probability of second candy being sour: p(second sour) = 2/5

Combined probability: 4/6 * 2/5 = 8/30

Probability of first candy being sour: p(first sour) = 2/6

Probability of second candy being sweet: p(second sweet) = 4/5

Combined probability: 2/6 * 4/5 = 8/30

Add the two probabilities: 8/30 + 8/30 = 16/30 = 8/15

8/15

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

step-by-step explanation: