Consider the line . find the equation of the line that is perpendicular to this line and passes through the point (-4, 5) find the equation of the line that is parallel to this line and passes through the point (-4, -5) equation of perpendicular: equation of parallel line:

we are given equation of line

Equation of perpendicular line:

Firstly , we will find slope of line

we can compare it with

y=mx+b

we get

we know that

slope of perpendicular line will be -1/m

so, slope is

It passes through point (-4,5)

so, we can use point slope form of line

we get

..........Answer

Equation of parallel line:

Firstly , we will find slope of line

we can compare it with

y=mx+b

we get

we know that

slope of parallel line always equal

so, slope is

It passes through point (-4,-5)

so, we can use point slope form of line

we get

............Answer

v v cj van config k tbs eng r.c r.c fcb fb gb frfr

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!