~asap offering 25 points answer all questions~ i will mark brainiest and rate 5 stars if correct this is consumer math btw( dont delete this))

This looks a lot more like business math than consumer math.

For all inventory balance problems, you add the input to the balance and you subtract the outflow from the balance.

11. 76 - 36 + 44 = 84

13. As with the previous months in the chart, the opening balance is the ending balance of the previous month. For March, that's February's ending balance: 210.

16. 193 + 23 + 45 - 45 - 100 = 116.

18. We know that all of the 145 received on 5/19 are included in the 150 in inventory. In addition, 5 of the units received on 5/8 also remain in inventory. The inventory value will be

... 145×$9.90 + 5×$9.75 = $1484.25

21. The reorder point is 4 + 21 = 25 days' inventory. If 750 tents represents 30 days' inventory, then the reorder point of 25 days' inventory is

... (25/30)×(750 tents) = 625 tents

If you do what the Hint asks, you find the daily usage is (750 tents)/(30 days) = 25 tents/day. Then the safety stock is 4×25 = 100 tents, and the number of tents used during the lead time is 21×25 = 525 tents. The total of these is 100+525 = 625 tents. (Note we have done 4 calculations instead of 2, and have had to manage 2 intermediate results.) It is much simpler just to count days, IMO.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source