What are the solutions of the equation (x+2)^2-2(x+2)-15=0

(x+2)^2-2(x+2)-15=0

x^2 + 4x + 4 -2x -4 - 15 = 0

x^2 + 2x - 15 = 0

(x + 5)(x - 3) = 0

x +5 = 0; x = -5

x - 3 = 0; x = 3

Answer

x = -5 , 3

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3