One rectangle has a base of 12 inches and an altitude of 6inches, the other has a base of 10 inches and an altitude of 5 inches. what is the ratio of the first rectangle to the second? and wat is the area of the first rectangle?

Sides of first rectangle are 12 inches and 6 inches

and sides of second rectangle are 10 inches and 5 inches

So to find the ration of sides we can do

Ratio of bases = 12/10 = 6/5

Ratio of altitudes = 6/5

Area of first rectangle = base * altitude = 12 *6 = 72 square inches

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it