Really need some find the value of x. can anyone also include the steps so i can understand it?

This one is a bit more challenging than the usual fare.

I'm always curious when something's crossed out.

I think you got the hard part right, that the equal arcs imply this is an isosceles triangle, JK=FJ. The angle x we seek is the opposite the base.

The trick is to draw the center C. Then CJ bisects angle x because of the isosceles triangle thing.

We get isosceles triangle FCJ where CF=CJ because they're both radii.

So angle CFJ = angle CJF = x/2.

A radius and a tangent make a right angle, so CFG is right and CFJ is complementary to GFJ=56 degrees.

CFJ = 90 - 56 = 34 degrees

x = 2 CFJ = 68 degrees

C

30

step-by-step explanation:

idk

i hope i