Avertical pole 6 feet long casts a shadow 55 inches long. find the angle of elevation of the sun. draw a diagram and find the angle of elevation of the sun. a.) 6.2° b.) 37.4° c.) 53.0°

A vertical pole(AB) 6 feet long casts a shadow(CB) 55 inches long as shown in the attached image. Since the angle of elevation of sun is . We hav to find the value of .

Firstly, we will change the dimensions of pole(in feet) to the dimension of shadow( in inches) . So, that the dimensions of pole and shadow are same.

Since, 1 feet = 12 inches.

6 feet = inches.

Now, let us consider the triangle ABC in the attached image,

We have to find

=

= 1.309

Length of the pole is = 6 feet=6*12=72 inches

Length of shadow of the pole = 55 inches

Here we use tangent function which relates height and shadow . Let the angle of elevation be x .

x= 52.6 degree= approx 53 degree

So the correct option is C.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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step-by-step explanation: