Identify the equation of the circle that has its center at (10, 24) and passes through the origin.

we are given

center=(h,k)=(10,24)

so,

h=10 and k=24

and it passes through origin

so, we can find radius

radius will be distance between (10,24) and (0,0)

now, we can use standard equation of circle

so, we will get equation as

..........Answer

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

a) 0,0; 1,1; and 2,2

step-by-step explanation:

these have the exact same coordinates, thus they are the correct function.