Abag contains 3 blue marbles and 2 green marbles. what is the probability of drawing a blue marble followed by a green marble, without replacing the first marble?

50% because when you take out the first marble witch is probably blue since there are more blue you would have 2 blue and 2 green so the chance would be 50%

Hello!

First of all, we have the probability of getting a blue marble, 3/5. If we were to get one, we would only have 4 left. Therefore we would have 2/4, or 1/2 chance of selecting a green marble.

We multiply our probabilities.

3/4(1/2)=3/8

Therefore, there is a 3/8 or about a 36% chance.

I hope this helps!

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60