In a given course a student receives preliminary examination grades of 81, 85, and 95. the final examination is weighed for one-third and the average of the preliminary grades is weighed as 2/3 of the final grade. what should the final examination grade be for a semester average of 90?

The average of the 3 grades = (81+85+95) /3 =87

This counts as 2/3 of the final grade:

87 * 2/3 = 58 points

For a grade of 90, they still need 90 -58 = 32 points

Let x = final exam score

The final exam is worth 1/3, so we get:

1/3x = 32

To get x, multiply both sides by 3:

x = 32 *3

x = 96

They need a 96 on the final exam.

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

b i think

step-by-step explanation:

not really sure