Solve the system of equations. 2x + 3y = 6 x + 4y = -2 x = 0, y = 2 x = 6, y = -2 x = 2, y = -1 x = 3, y = 0

2x+3y=6
X+4y=-2

You have to make the x have the same numbers, so you have to multiply by the opposite. This means; 1(2x+3y=6)
2(x+4y=-2)

2x+3y=6 2x+8y=-4
Now subtract inorder to have y only.
2x-2x=0 3y-(+8)=-5y 6-(-4)=10
-5y=10
-y=2
Y=-2

To find x, substitute y in any of the first equations given
2x+3(-2)=6
2x-6=6
2x=6+6
2x=12
X=6

Y=-2 X=6

To see if I am correct, substitute x and y in any of the first equations

X+4y=-2
6+4(-2)=-2
6-8=-2
-2=-2
Substitute in the other equation also to be sure.

hope this is what you were asking for!

step-by-step explanation: