Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3x + 3.

Parallel lines have the same slope, but different y-intercepts

The slope of both lines is -2/3

To find the equation that passes through (7, 3) we can use the point-slope formula: y - y1 = m (x - x1)

y - (3) = (-2/3) (x - (7))

y - 3 = -2/3x + 4 and 2/3

y = -2/3x + 7 and 2/3

or

y = -2/3x + 7.67

:)))

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer: sine

step-by-step explanation: