Use the equation and type the ordered-pairs. y = log₂ x (1/ ( ( ( ( (}

Hello!

To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.

y = log₂ 1/2, y = -1

y = log₂ 1, y = 0

y = log₂ 2, y = 1

y = log₂ 4, y = 2

y = log₂ 8, y = 3

y = log₂ 16, y = 4

Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )