Identify an equation in slope – intercept‘s form for the line parallel to y=5x+2 that passes through (-6,-1).

Slope-intercept form of a line is y=mx+b where m= slope and b=y-intercept.

First step is to compare this line with the given line y=5x+2 to get the value of m.

After comparing we will get m=5.

Now slope of all parallel lines are equal which means if slope of this line is 5 then slope of the line which is parallel to this line will also be 5.

Point- slope form of a line is:

Given the line passes through (-6,-1). So, plug in x1=-6, y1=-1 and m=5 in the above equation. So,

y-(-1)=5(x-(-6))

y+1=5(x+6)

y+1=5x+30

y=5x+30-1

y=5x+29.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.