What is the remainder rrr when the polynomial p(x)p(x)p, left parenthesis, x, right parenthesis is divided by (x++4)? left parenthesis, x, plus, 4, right parenthesis, question mark \qquad p(x) = -3x^3-10x^2+5x-12p(x)=−3x 3 −10x 2 +5x−12?

We can use synthetic division to divide by (x+4).

So, divisor will be x+4=0

Hence, x+4-4=0-4

x=-4.

Next step is to write all the coefficient and the constant in order. I am attaching the synthetic division method in a file by using the following stpes.

Step 1: Carry down the first leading coefficient 3.

Step 2: Multiply this coefficient 3 with the divisor -4 which will reslu (-3)*(-4)= 12.

Step 3: Place this 12 in the second colum and then add.

Hence, repeat this method till the constant .

At the last place we will get the remainder which is 0.

So, remainder is 0.

2x^2+5x+17

your welcome. : )

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step-by-step explanation: