Tyrell is going to be use asa to prove that pqr=sqr

Presumably our goal is to show PRQ=SRQ, PQR=SQR and QR=QR for ASA.

A. QR=QR is the reflexive property; things are congruent to themselves, TRUE

B. We need to prove that, but it doesn't have anything to do with the symmetric property.

C. PQ=SQ isn't something we'd need to show for our ASA proof

D. Again, not the symmetric property.

A

A. Prove that QR≅QR by the reflexive property.

Step-by-step explanation:

ASA postulate says that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle then the triangles are said to be congruent.  

In the given triangles ΔPQR and ΔSQR

∠PQR ≅∠SQR     {given}

∠QRP ≅ ∠QRS     {given}

In the figure , the included side of ∠PQR and ∠QRP= QR

The included side of ∠SQR  and ∠QRS =OR

So we need to probe QR≅QR by Reflexive property, to prove triangles ΔPQR and ΔSQR are congruent.