Brandon is thinking of a number that is divisible by 6 and 8 . what is the smallest number that brandon could think of

since

6 = 2 * 3 <--- two factors

8 = 2 * 2 * 2 <--- three factors

and since the "2" is there on each, then we can just use that instance of it once.

so instead of using 2 * 3 * 2 * 2 * 2, we'll use 2 * 3 * 2 * 2, and that is our LCD.

2 * 3 * 2 * 2 = 24.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.